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$$
1=\sqrt[3]{\frac{13\sqrt{3}}{36}+\frac{5}{8}}-
\sqrt[3]{\frac{13\sqrt{3}}{36}-\frac{5}{8}}
\qquad 
2=\sqrt[3]{6\sqrt{3}+10}-
\sqrt[3]{6\sqrt{3}-10}
$$
More generally, for arbitrary $c$,
$$
1=\sqrt[3]{\frac{1}{8}+\frac{c^2}{2}+\frac{c(4c^2+9)\sqrt{3}}{36}}+
\sqrt[3]{\frac{1}{8}+\frac{c^2}{2}-\frac{c(4c^2+9)\sqrt{3}}{36}}
$$

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